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Let
be an inner product space. A vector is a unit vector if . are orthogonal if . A subset
is orthogonal if any two distinct elements of are orthogonal A subset
is orthonormal if is orthogonal and consists entirely of unit vectors. - If
then is orthonormal if and only if Whereis the Kronecker delta.
- If
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(Friedberg e6.1.10) Pythagorean Theorem Analogue If
are orthogonal elements of then -
(Friedberg e6.1.12) Let
be an orthogonal set in and . Then -
(Friedberg 6.3) Let
be an inner product space and let be an orthogonal set of nonzero vectors. IfThen
- (Friedberg 6.3.1) If
above is orthonormal, then - (Friedberg 6.3.2) Let
be an inner product space. Let be an orthogonal set of nonzero vectors. Then is linearly independent.
- (Friedberg 6.3.1) If
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(Friedberg 6.4) Let
be an inner product space and let be a linearly independent subset of . Define where andFor
Then
is an orthogonal set of nonzero vectors such that .This construction is called the Gram-Schmidt Orthogonalization Process.
- An orthonormal basis can then be obtained by applying the Gram-Schmidt Orthogonalization process and dividing by the norm of the vectors.
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(Friedberg 6.5) Let
be a finite dimensional inner product space. Then has an orthonormal basis . Furthermore, if and . Then- (Friedberg 6.5.1) Let
be an orthonormal basis and a linear operator on and let . Then
- (Friedberg 6.5.1) Let
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Let
be an orthonormal subset of an inner product space and . The Fourier coefficients of relative to are the scalars where . -
Let
be an inner product space and . Then is the orthogonal complement of defined as the set of all vectors in orthogonal to every vector in . That is is a subspace for any .
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(Friedberg 6.6) Let
be a finite dimensional subspace of an inner product space . If is an orthonormal basis of and thenWhere
. This representation of is unique. That is is unique.-
(Friedberg 6.6.1)
Is the unique vector in
that is “closest” to . That is, if thenAnd also
.We call
the orthogonal projection of on -
(Friedberg e6.2.6) If
there exists such that but .- Intuition: Use (Friedberg 6.6). We have that
assuming and by the fact that (otherwise ), we have
- Intuition: Use (Friedberg 6.6). We have that
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(Friedberg 6.7) Suppose that
is an orthonormal set in an -dimensional inner product space . Then can be extended to an orthonormal basis for using additional elements- If
then the set is an orthonormal basis for - If
, then . In fact (Fraleigh 6.2.12d) (see here).
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(Friedberg e6.2.11) Let
, where is an inner product space. Then -
(Friedberg e6.2.12) Let
be an inner product space, and be a finite dimensional subspace of . We have so that .
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(Friedberg e6.2.13a) Parseval’s Identity. Let
be an orthonormal basis for . For any we have -
(Friedberg e6.2.14) Bessel’s Inequality Let
be an inner product space and be any orthonormal subset of . For any we have -
Let
be an inner product space and be a projection. is an orthogonal projection if -
Orthogonal Projections are uniquely determined by their range.
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(Friedberg 6.23) Let
be an inner product space and be a linear operator on . Then is an orthogonal projection if and only if
Geometric Interpretation
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Let
be a linear operator on a finite-dimensional real inner product space . is a rotation if is the identity on or if there exists a two dimensional subspace of , an orthonormal basis for and a real number such thatAnd
for all .We refer to
as the axis of rotation. is called a rotation of about . -
Let
be a linear operator on a finite-dimensional real inner product space . The operator is called a reflection if there exists a one-dimensional subspace of such thatWe say that
is a reflection of about . -
(Friedberg 6.38) Let
be an orthogonal operator on a two dimensional real inner product space . Then is either a reflection or a rotation.Also
is a reflection if and only if the Determinant is a rotation if and only if .- (Friedberg e6.10.8) No orthogonal operator can be both a rotation and a reflection.
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(Friedberg 6.38.1) Let
be a two dimensional real inner product space. The composition of a reflection and a rotation on is a reflection on . -
(Friedberg 6.39) Let
be an orthogonal operator on a nonzero finite dimensional real inner product space . Then there exists a collection of pairwise orthogonal -invariant subspaces of such that- The restriction of
to is either a rotation or a reflection. - (Friedberg 6.40)
- The number of
’s for which is a reflection is even or odd according to whether or . - It is always possible to decompose
as shown so that the number of ’s for which is a reflection is zero or one according to whether or . Also if is a reflection then .
- The number of
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(Friedberg 6.40.1) Let
be an orthogonal operator on a finite dimensional real inner product space . Then there exists a collection of orthogonal operators such that- Each
is either a rotation or a reflection - For at most one
, is a reflection. -
- Each