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Let
be a Vector Space and a nonempty subset of . A vector is a linear combination of elements in if there exists a finite number of elements and scalars such that -
(Fraleigh 30.16) Let
be a vector space over field and . If is a linear combination of vectors and each , is a linear combination of vectors . Then is a linear combination of the .
Linear Independence
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A subset
of a vector space is said to be linearly dependent if there exists a finite number of distinct vectors and scalars such that Otherwise,
and its elements are said to be linearly independent -
Any subset containing the zero vector must be linearly dependent
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The following are true about linear independence for any vector space
is linearly independent. - A set consisting of a single non-zero vector is linearly independent.
- For a linearly independent set, the only way to get the zero vector is by setting
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(Friedberg 1.6) Let
. If is linearly dependent, then so is An immediate corollary: Let
. If is linearly independent, then so is -
A maximal linearly independent subset of
is a subset of such that is linearly independent - Any subset of
that properly contains is linearly dependent.
Span and Basis
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(Friedberg 1.5) If
is a nonempty subset of a vector space , then the set consisting of all linear combinations of elements of is a subspace of . Moreover, is the smallest subspace of containing . We call
the span of , denoted . We define
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A subset
of a vector space generates if . -
A basis
for a vector space is a linearly independent subset of that generates . We say that the elements of form a basis for . A basis can be ordered if the order of the elements in the basis is important. We can generalize this definition to say that a basis is a maximal linearly independent subset of
(see Friedberg 1.12) -
(Friedberg 1.7) Let
be a vector space and . Then is a basis for if and only if each vector can be uniquely expressed as a linear combination of the form -
(Friedberg 1.8) Let
be a linearly independent subset of a vector space that is not in . Then if and only if -
(Friedberg 1.9; Fraleigh 30.18) If
is generated by a finite set , then a subset of is a basis for . Hence, has a finite basis. -
(Friedberg 1.10) Basis Replacement Theorem / Steinitz Replacement Lemma Let
be a vector space having a basis containing exactly elements. Let be a linearly independent subset of containing elements. There exists
containing exactly elements such that In other words, each element in the basis is replaceable.
- (Friedberg 1.10.1) Any linearly independent subset of
containing exactly elements is a basis for . - (Friedberg 1.10.2) Any subset containing more than
elements is linearly dependent. Any linearly independent subset of contains at most elements - (Friedberg 1.10.3; Fraleigh 30.20) Every basis for
contains exactly elements. - (Friedberg 1.10.4) Let
be a subset of such that and has at most elements, then is a basis for . - (Friedberg 1.10.5; Fraleigh 30.19) Extension Property Let
be a linearly independent subset of . Then, there exists such that is a basis for . Every linearly independent subset of can be extended to a basis for
- (Friedberg 1.10.1) Any linearly independent subset of
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The dimension of a vector space is the unique number of elements in each basis of
, denoted . A vector space is finite-dimensional if the dimension is finite and infinite-dimensional otherwise. -
(Friedberg e1.6.19,; Fraleigh 30.17) Let
, and . Then a subset of is a basis for . Moreover, contains at least at least elements. -
(Friedberg 1.12) Let
be a vector space and a subset that generates . If is a maximal linearly independent subset of , then is a basis for . -
(Friedberg 1.13) Let
be a linearly independent subset of a vector space . There exists a maximal linearly independent subset of that contains . Therefore, alongside (Friedberg 1.12) Every vector space has a basis.