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Given an arbitrary orientation to the edge set
, the graph Laplacian can be defined as - The Laplacian is self-adjoint and positive semi-definite
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The Laplacian associated with a weighted graph is given by
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We may define an Edge Laplacian for any
defined as - The set of nonzero eigenvalues of
is equal to the set of nonzero eigenvalues of - The nonzero eigenvalues of
and are equal to the square of the nonzero singular values of . - If
has connected components , the edge Laplacian of has a block diagonal form This can be interpreted as an adjacency matrix, where edges that share common vertices are considered non-adjacent.
- The set of nonzero eigenvalues of
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For any digraph, the vector of all ones is the eigenvector associated with the zero eigenvalue of
- The in-degree version of the Laplacian captures how a node is influenced by others.
- The out-degree version of the Laplacian captures how a node influences other nodes.
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(Mesbahi e2.5) Let
be a graph, then-
Intuition: The adjacency matrix can be arranged as a block diagonal matrix through reordering of matrices. The rank of which is known to be the sum of the ranks of the block matrices).
Let
be a block in the Laplacian with . Then, . This is the case because is positive semi-definite. Therefore it has as an eigenvalue exactly once (by Mesbahi 2.8).
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(Mesbahi 2.8) Let
be the Laplacian of . Sort the eigenvalues as . We refer to this listing as the **Laplacian spectrum is connected if and only if since is positive semi-definite. This corresponds to the eigenvector of all s (and it is because the sum of any row on an incident matrix is ).- Using the Spectral Properties of the Laplacian, we can extend the connectivity inequality
Provided that
is not the complete graph.
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(Mesbahi 2.9) Kirchhoff’s Matrix tree Theorem Consider the graph
with vertices and edges. Then using the determinantfor any vertex
.(Mesbahi 2.10, Wilson 10.3) Let
be the number of spanning trees in . ThenIn other words, the number of spanning trees of
is equal to the cofactor of any element of .(Mesbahi 2.12) A directed graph version can be defined as follows. Let
be an arbitrary vertex of a weighted digraph . ThenWhere
is the set of spanning -arborescences in . -
(Mesbahi 3.8) A digraph
on vertices contains an arborescence if and only ifIn that case
is spanned by the vector of all ones. -
(Mesbahi 3.10) Let
be a weighted digraph on vertices. By the Gerschgorin Disk TheoremWhere
is the maximum weighted in-degree in .Thus, every eigenvalue of
has non-negative real parts. -
(Mesbahi 3.11) Let
be the Jordan decomposition of the in-degree Laplacian for . When contains an arborescence, thee nonsingular matrix can be chosen such thatWhere
is the Jordan block associated with , and each has positive real parts.This implies that
And
Where
is the first column of and the first row of .
Factorization Lemma
- (Mesbahi 3.22) Let
be graphs on and vertices respectively. ThenThat is, The Laplacian of the Cartesian Product is the Kronecker sum of the Laplacians of the individual graphs. - (Mesbahi 3.23) Let
be graphs on and vertices such that and respectively have as eigenvalues: and with associated eigenvectors and . ThenIs the eigenvector associated with the eigenvalue of .