• is normal if its left and right cosets coincide i.e.

. We denote this with .

  • A group is a simple group if it is nontrivial and has no proper nontrivial normal subgroups.

    • That is, it does not have a factor group that is not the trivial subgroup or the group itself.
  • (Fraleigh 14.13) The following are equivalent conditions for to be normal. and , the following holds

  • (Fraleigh e14.31) Let , then the intersection is also normal

  • (Fraleigh e14.34) If has exactly one subgroup of a given order, then is a normal subgroup of .

  • A maximal normal subgroup of a group is a normal subgroup such that there is no proper normal subgroup

  • (Fraleigh 15.18) is the maximal normal Subgroup of if and only if is simple.

  • (Fraleigh 34.4) If and , then

    Also if is also normal in , then is also normal in .

    • Idea: To show the theorem, show that is a subgroup of . Since is the smallest subgroup containing , clearly if is a subgroup .
  • Let and . Then

  • (Fraleigh 35.10) Zassenhaus Lemma / Butterfly Lemma. Let and and . Then

    • Proof: Let and be defined as the theorem. Clearly all products involved are groups by (Fraleigh 34.4). To show the normal subgroup relation, we must show that and similarly . All normal subgroup relations in the theorem then follow immediately from (Fraleigh 34.4).

      Let

      To show the isomorphism, define the homomorphism such that for and , we have

      It is easy to show that is a well-defined homomorphism. It is also onto. Thus

      Therefore . The First Isomorphism Theorem guarantees the isomorphism.

Butterfly Lemma. Bold Lines indicate Normal Subgroup relations. The quotient groups formed from these relations are isomorphic. Image taken from Fraleigh

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